Question

Find three consecutive odd integers so that the sum of twice the first, the second

and three times the third is 152.

Answer 1

Answer: 23, 25, 27

Explanation:

Let the 3 consecutive odd numbers be x, x+2 and x+4.

So

2x+(x+2)+3(x+4)=152

2x + x + 2 + 3x + 12 = 152

6x+14=152

6x = 152 - 14

x=138/6

x=23

So, the numbers are 23, 25 and 27.