Question

Find the x-value of the removable discontinuity of the function. ​

Answer 1

x=2

Explanation:

`f(x)=(x^2-4)/(x^2-12x+20)`

Factor the numerator and denominator:

`f(x)=((x-2)(x+2))/((x-2)(x-10))`

We can remove (x-2) from the function:

`f(x)=(x+2)/(x-10)`

(x-2) is a removable discontinuity.

The x-value of x-2 is x=2.