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User Tvirtualw
by
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1 Answer

1 vote

Answer:

The answer is


$ (3x^2 - 12x + 43) + (-190)/((x+4)) $

Where

Remainder = -190

quotient =
3x^2 - 12x + 43

Explanation:

The dividend is given as


3x^3 - 5x -18

The divisor is given as


x + 4

Using the long division,

Multiply
(x + 4) by
3x^2

Remainder:


-12x^2 - 5x -18

Multiply
(x + 4) by
-12x

Remainder:


43x - 18

Multiply
(x + 4) by
43

Remainder:


-190

Therefore, the answer is


$ (3x^2 - 12x + 43) + (-190)/((x+4)) $

Where

Remainder = -190

quotient =
3x^2 - 12x + 43

User Nir Hartmann
by
8.4k points

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