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K here’s another one please help

K here’s another one please help-example-1

1 Answer

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Answer:

Both the relations are functions, the correct answer is a.

Explanation:

In order to solve this problem we will first find the inverse relation as shown below:


y = 3x^2 + 5\\x = 3y^2 + 5\\3y^2 = x - 5\\y^2 = (x - 5)/(3)\\y = \sqrt{(x - 5)/(3)} = (√(x - 5))/(√(3))\\y = (√(x - 5)√(3))/(√(3)√(3)) = (√(3x - 15))/(3)

Functions are relations between two groups of numbers, for which the input must generate only one output. Using this definition we can classify both the relation and its inverse as a function, therefore the correct answer is a.

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