Answer:
We can express the equation for any linear equation with slope -2 and point (x0,y0) as:
![y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)](https://img.qammunity.org/2021/formulas/mathematics/college/mjc4rppheunefur6gll5lb42yzyn7dltoi.png)
Explanation:
Incomplete question:
There is no point to complete the equation.
As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.
The linear equation can be written generically as:
![y(x)=mx+b\\\\y(x)=-2x+b](https://img.qammunity.org/2021/formulas/mathematics/college/3fxyi9b7wfbo53orercg025h1vb84fpr3p.png)
If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:
![y_0=-2x_0+b](https://img.qammunity.org/2021/formulas/mathematics/college/qxsqysafk8cn5sheruhnw64dwxleydy710.png)
Then, we can calculate b as:
![y_0=-2x_0+b\\\\b=y_0+2x_0](https://img.qammunity.org/2021/formulas/mathematics/college/qxst3j1tmxbchbs1u9uj72tozvt4xpbxv9.png)
We can express the equation for any linear equation with slope -2 and point (x0,y0) as:
![y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)](https://img.qammunity.org/2021/formulas/mathematics/college/mjc4rppheunefur6gll5lb42yzyn7dltoi.png)