Answer:
x = 4
Explanation:
The equation given is a radical equation, we will solve using the steps below:
√x+5 + √x = 15÷√x+5
√x+5 + √x =
![(15)/(√(x+5) )](https://img.qammunity.org/2021/formulas/mathematics/high-school/9o0jcvmmy4qrpb9gl8kpi49lsxopaez7x8.png)
Multiply both-side of the equation by
![√(x+5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/uo6kedq9kqfqkbtw466ljjus8vssiu0igp.png)
(√x+5 + √x) =
×
----------------------------------(2)
Note
×
= x +5
Also at the right-hand side of the equation
cancel-out
leaving us with just 15
so equation(2) becomes
x+5 +√x
= 15
subtract 5 from both-side of the equation
x+5-5 +√x
= 15-5
x +√x
= 10
subtract x from both-side of the equation
x-x +√x
= 10-x
√x
= 10-x
square both-side of the equation
(√x
) ² = ( 10-x)²
x (x+ 5) = ( 10-x)(10-x)
open the bracket
x² + 5x = 100 - 20x + x²
subtract x² from both-side of the equation
x² - x² + 5x = 100 - 20x + x² - x²
5x = 100 - 20x
collect like term
5x + 20x = 100
25x = 100
divide both-side of the equation by 25
25x/25 = 100 /25
x = 4