Question

Solve the quadratic equation by using a numeric approach. x squared + 1.1 x minus 2 = 0 a. x = 1.7 and x = -29.2 c. x = 2.3 and x = -22.2 b. x = 3.7 and x = 29.2 d. x = 1.9 and x = -22.2

Answer 1

A on edge 2021. Just took practice quiz.

Explanation:

x = 1.7 and x = -29.2

Answer 2

None of the options are correct, the correct answers are: x = 0.967 and -2.067

Explanation:

`x^2 + 1.1x - 2 = 0`

Comparing this equation with
`ax^2 + bx + c = 0`

a = 1, b = 1.1, c = -2

Using the almighty formula for solving quadratic equation:

`x = (-b \pm √(b^2 - 4ac) )/(2a) \\x = (-1.1 \pm √(1.1^2 - 4(1)(-2)) )/(2(1)) \\x = (-1.1 \pm √(1.1^2 - 4(1)(-2)) )/(2(1)) \\x = (-1.1 \pm 3.035 )/(2)\\x_1 = (-1.1 + 3.035 )/(2) = 0.967\\x_2 = -(-1.1 - 3.035 )/(2) = -2.067`