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You weigh six packages and find the weights to be 26, 18,58,22,54,and 50 ounces. If you include a package that weighs 66 ounces, which will increase more, the median or the mean?

User Yunfei Gu
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2 Answers

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Answer: The mean which is also known as the average is determined by dividing the sum of the weight of the packages by the total number of packages. From the information given, Mean = (26 + 18 + 58 + 22 + 54 + 50)/6 = 38If you include a package that weighs 66 ounces, the new mean would be New mean = (26 + 18 + 58 + 22 + 54 + 50 + 66)/7 = 42For the median, we would rearrange the weights in ascending order. It becomes18, 22, 26, 50, 54, 58Median = (26 + 50)/2 = 38By adding the new weight, it becomes18, 22, 26, 50, 54, 58, 66New median = 50It can be seen that both the median increased by more. It increased by 12 while the mean increased by 4

Explanation:

User Eddyq
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1 vote

Answer:

Explanation:

The mean which is also known as the average is determined by dividing the sum of the weight of the packages by the total number of packages. From the information given,

Mean = (26 + 18 + 58 + 22 + 54 + 50)/6 = 38

If you include a package that weighs 66 ounces, the new mean would be

New mean = (26 + 18 + 58 + 22 + 54 + 50 + 66)/7 = 42

For the median, we would rearrange the weights in ascending order. It becomes

18, 22, 26, 50, 54, 58

Median = (26 + 50)/2 = 38

By adding the new weight, it becomes

18, 22, 26, 50, 54, 58, 66

New median = 50

It can be seen that both the median increased by more. It increased by 12 while the mean increased by 4

User Daniel Eberl
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4.3k points
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