Question

In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, assume the radius of the orbit is 5.29 10-11 m. (a) Find the magnitude of the electric force exerted on each particle.

Answer 1

`F=9.06*10^(-8) N`

Step-by-step explanation:

We can use the Coulomb force

`F=k(q_(e)q_(p))/(r^(2))`

`F=9*10^(9)(|-(1.6*10^(-19))^(2)|)/((5.29*10^(11))^(2))`

`F=9.06*10^(-8) N`

The direction of the force is toward proton with respect to the electron reference coordinate and is in the direction of the electron in the proton system reference.

I hope it helps you!