Final answer:
The reaction 4A + B ⇌ 3C, when multiplied by 2, becomes 8A + 2B ⇌ 6C. The new equilibrium equation shows doubled coefficients, yet the equilibrium constant remains the same because the substance ratios don't change.
Step-by-step explanation:
When the equilibrium reaction 4A + B ⇌ 3C is multiplied by a factor of 2, the new equilibrium equation becomes 8A + 2B ⇌ 6C. This is achieved by doubling the coefficients for each substance in the reaction. However, it's important to note that although the equation looks different, the actual position of equilibrium doesn't change because the ratios of the substances are still the same. Therefore, while the coefficients have been scaled, the underlying chemistry and the equilibrium constant remain unaffected. You can verify this by using the law of mass action which states that for a reversible reaction at equilibrium at a constant temperature, the equilibrium constant (K) is defined by the concentrations (or, in the case of gases, the partial pressures) of the reactants and products.