Answer:
Tension, T = 0.556 N
Step-by-step explanation:
It is given that,
Length of vocal cords, l = 22 mm = 0.022 m
Mass per unit length,
![\mu=0.0042\ kg/m](https://img.qammunity.org/2021/formulas/physics/college/l6j41ehp0d49tuq9rhn8kb8te7er3mwzi9.png)
We need to find the tension is required in the vocal cords in order to produce a tone of middle C of frequency 261.62 Hz. The frequency in terms if tension is given by :
![f=(1)/(2l)\sqrt{(T)/(\mu)}](https://img.qammunity.org/2021/formulas/physics/college/oc083pz2qeibw8m2vad7oa455pkc6kxbto.png)
T = tension in the vocal cords
![f^2=(1)/(4l^2)* (T)/(\mu)\\\\T=4l^2\mu f^2\\\\T=4* (0.022)^2* 0.0042 * (261.62 )^2\\\\T=0.556\ N](https://img.qammunity.org/2021/formulas/physics/college/9w0r99v7t26w016blgg1or7vbt2cun9sje.png)
So, the tension in the vocal cords is 0.556 N.