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If f(x) = x^2-x , find 2f (3)+1

HELP plzzz!

2 Answers

5 votes

Answer:


\huge\boxed{2f(3)+1=13}

Explanation:


f(x)=x^2-x\\\\2f(x)+1=2(x^2-x)+1=2x^2-2x+1\\\\\text{put}\ x=3\ \text{to the equation}\\\\2f(3)+1=2(3^2)-2(3)+1\\\\\text{Use PEMDAS}\\\\2f(3)+1=2(9)-6+1=18-6+1=12+1=13

User Ironmouse
by
4.3k points
1 vote

Hello!

Answer:

13.

Explanation:

Given f(x) = x² - x

Solve for 2 · f(3) + 1

Substitute in 3 for 'x' to find the value of f(3):

f(3) = (3)² - (3)

Simplify:

f(3) = 9 - 3 = 6

Plug this into the second equation:

2(6) + 1 = 12 + 1 = 13.

User VirCom
by
4.6k points