Question

The decomposition of H2O2 is first order in H2O2 and the rate constant for this reaction is 1.63 x 10-4 s-1. How long will it take for [H2O2] to fall from 0.95 M to 0.33 M?

Answer 1

It will take 6486.92 minutes for [H2O2] to fall from 0.95 M to 0.33 M

Step-by-step explanation:

The order of reaction is defined as the sum of the powers of the concentration terms in the equation. Order of a reaction is given by the number of atoms or molecule whose concentration change during the reaction and determine the rate of reaction.

In first order reaction;

`In (a)/(a_o-x)= k_1 t`

where;

a = concentration at time t

`a_o` = initial concentration

and k = constant.

`In ((0.33)/(0.95))= -1.63 * 10^(-4) * t`

`-1.05736933 = -1.63 * 10^(-4) * t`

`t = (-1.05736933)/( -1.63 * 10^(-4) )`

t = 6486.92 minutes