Question

Given: DF and DE are midsegments of ∆ABC Prove: DE= 1/2 AC (PLEASE HELP)

Answer 1

The correct answer is D because we proved that the triangles ΔDBE and ΔADF are congruent so that means that DE = segment A F because of CPCTC.

Explanation:

Answer 2

The correct answer is D because we proved that the triangles ΔDBE and ΔADF are congruent so that means that DE = segment A F because of CPCTC.