Question

4 (5 points)

What is the range of y =|3x + 1)?
a) {y\y >0}
b) {y\y > 1}
8
c) {all real numbers)
d) {y|y23]

Answer 1

[0, infinity)

Explanation:

clarence, I believe you meant y = |3x + 1|. The absolute value of 3x + 1 is never less than 0, so the range of the given function (above) is [0, infinity).