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If 2 moles of helium undergo a temperature increase of 100 K at constant pressure, how much energy has been transferred to the helium as heat

User Mornor
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1 Answer

1 vote

Answer:


Q=4154J

Step-by-step explanation:

Hello,

In this case, the involved heat in this heating process is considered to be computed via:


Q=nCp\Delta T

Whereas we assume a constant molar specific heat of helium which is 20.77 J/(mol*K), thus, the transferred energy in the form of heat turns out:


Q=2mol*20.77(J)/(mol*K) *100K\\\\Q=4154J

Regards.

User Hiws
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