Answer: Water: 120 gallons
Premium Antifreeze: 200 gallons
Explanation:
Had to complete the question first.
A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 80% pure antifreeze. The company wants to obtain 320 gallons of a mixture that contains 5% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed?
Water: ____ gallons
Premium Antifreeze: _____ gallons
Solution:
Let w = amt of water required
An equation based on the the percent water, an 80% solution is 20% water
Multiply through
= 20% (320 - w) + w = 50% x ( 320)
64 - 0.2w + w = 160
Collecting like times
0.8w = 160 - 64
w = 96%
w = 120 gal of water to produce 320 gal of 50% antifreeze
320 - 120 = 200 gal of 80% solution
Water: 120 gallons
Premium Antifreeze: 200 gallons