Question

A 0.410 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 35.0 pC charge on its surface. What is the potential (in V) near its surface

Answer 1

The potential is
`V = 153.659 \ V`

Step-by-step explanation:

From the question we are told that

The diameter of the plastic sphere is
`d = 0.410 \ cm = 0.0041 \ m`

The magnitude of the charge is
`q = 35.0 pC = 35.0 *10^(-12) \ C`

The radius of the plastic sphere is mathematically evaluated as

`r = (d)/(2)`

=>
`r = (0.0041)/(2)`

`r = 0.00205 \ m`

The potential near the surface is mathematically represented as

`V = (k * q)/(r )`

Where k is the Coulombs constant with value
`9 *10^(9) \ kg\cdot m^3\cdot s^(-4) \cdot A^(-2).`

substituting values

`V = (9*10^9 * 35 *10^(-12))/(0.00205)`

`V = 153.659 \ V`