Answer:
619.2 Hz and 582.5Hz
Step-by-step explanation:
Given that
Frequency of the generator, F(s) = 600 Hz
Length if the rope, r = 1 m
Speed of whirling, w = 100 rpm
For starters, we find the speed of the generator, v(g)
v(g) = r.w
It should be noted, however, that we are to convert the speed of whirling from rpm to rad/s, thus
100 rpm = 100 * 2π/60 rad/s
100 rpm = 200π/60
100 rpm = 620.4 / 60
100 rpm = 10.47 rad/s
Now, we use this to find the speed of the generator
v(g) = r.w
v(g) = 1 * 10.47
v(g) = 10.47 m/s
When approaching the generator, the frequency is calculated as
F(a) = F(s) / [1 - (v(g)/v)]
F(a) = 600 / [1 - (10.47/343)]
F(a) = 600 / 0.969
F(a) = 619.2 Hz
On the other hand, the receding generator frequency is
F(r) = F(s) / [1 + (v(g)/v)]
F(r) = 600 / [1 + (10.47/343)]
F(r) = 600 / 1.030
F(r) = 582.5 Hz
Therefore, we can conclude that the highest and lowest frequency is 619.2 Hz and 582.5 Hz respectively