Question

What volume is occupied by a 0.118 mol of helium gas at a pressure of 0.97 atm and a temperature of 305 K ? Would the volume be different if the gas was argon (under the same conditions) ?

Answer 1

See below

Step-by-step explanation:

PV = n RT R = .082057 L - Atm / (K-Mole)

.97 V = .118 (.082057)(305)

V = 3.04 liters

Will not change for argon.....will be the same for all ideal gases