167k views
4 votes
If the quadratic formula is used to solve 2x2-3x - 1 = 0, what are the solutions?

1-3 + fin 3 - i7)
4.
4.
0 -3-17 3 - 171
4
4

13 +17 3 - (1)
4
4

User Toidiu
by
6.7k points

1 Answer

5 votes

Answer:

x = (3 +/- sqrt(17) / 4.

Explanation:

x = [-(-3) +/- sqrt((-3)^2 - 4*2*-1)] / 4

x = (3 +/- sqrt(17) / 4.

User Darryl Braaten
by
5.7k points