Question

Six friends, four boys and two girls, went to a movie theater. They wanted to sit in a way so no girl sits on either first or last chair. How many such arrangements are possible?

Answer 1

288 possible seating arrangements.

Explanation:

There are 4 possible choices for the first seat.

There are 3 possible choice for the sixth seat.

There are 4 possible choices for the second seat.

There are 3 possible choices for the third seat.

There are 2 possible choices for the fourth seat

There is only 1 possible choices for the fifth seat.

4×3×4×3×2×1=

12×4×3×2×1=

48×3×2×1=

144×2×1=

288×1=

288 possible seating arrangements.