Question

Suppose the current is changing with time according to I = a + bt, where a and b are constants. Determine the magnitude of the emf (in V) that is induced in the loop if b = 14.0 A/s, h = 1.00 cm, w = 15.0 cm, and L = 1.05 m.

Answer 1

`emf=81.51* 10^(-7) Volt`

Step-by-step explanation:

Given that

I = a + b t

b = 14 A/s , h= 1 cm , w= 15 cm , L= 1.05 m

The magnitude of induced emf is given as follows

`emf=(d\phi)/(dt)`

`emf=(\mu_o* L)/(2* \pi)* ln(h+w)/(h)* (dI)/(dt)`

I = a + b t

`(dI)/(dt)= b`

Now by putting the values in the above equation we get

`emf=(4* \pi * 10^(-7)* 1.05)/(2* \pi)* ln(1+15)/(1)* 14`

`emf=81.51* 10^(-7) Volt`

Thus the induce emf will be

`emf=81.51* 10^(-7) Volt`