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The specific heat of water is about 4200 J/(kg·oC). To heat a cup of water of 0.25 kg from 10 oC to 50 oC, at least how much heat is required?

User Donya
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1 Answer

4 votes

Answer:

heat required = mass × specific heat × change in temperature

Step-by-step explanation:

0.25 × 4200 × 40

=42000 J

User Indgar
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