What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i? f(x) = x2 – 2x + 2 f(x) = x3 – x2 + 4x – 2 f(x) = x3 – 3x2 + 4x – 2 f(x) = x2

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What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i? f(x) = x2 – 2x + 2 f(x) = x3 – x2 + 4x – 2 f(x) = x3 – 3x2 + 4x – 2 f(x) = x2 – x + 2

asked Aug 4, 2021 168k views

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What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i? f(x) = x2 – 2x + 2 f(x) = x3 – x2 + 4x – 2 f(x) = x3 – 3x2 + 4x – 2 f(x) = x2 – x + 2

Mathematics
college

Blhsing asked

by Blhsing

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1 Answer

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C on edge is f(x) = x3 – 3x2 + 4x – 2

Explanation:

KRoy answered Aug 8, 2021

by KRoy

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