Question

Identify the equation of the circle that has its center at (9,12) and passes through the origin

Answer 1

(x -9)^2 +(y -12)^2 = 225

Explanation:

The equation of a circle with center (h, k) that passes through point (a, b) is ...

(x -h)^2 +(y -k)^2 = (a -h)^2 +(b -k)^2

For your given points, the equation is ...

(x -9)^2 +(y -12)^2 = (0 -9)^2 +(0 -12)^2 = 81 +144

(x -9)^2 +(y -12)^2 = 225