Question

Find the equation of a line parallel to −x+5y=1 that contains the point (−1,2)

Answer 1

Answer: y = 1/5x+ 2.2

Explanation:

First, change the expression into y-intercept form

-x+5y=1

5y=x+1

y=1/5x+1/5

For a line to be parallel to another line, it must have the same slope. Thus, the slope must be 1/5x. Then, to find the y-intercept simply do:

y = 1/5x+b, where x = -1 and y = 2

2=1/5(-1)+b

2 = -1/5+b

b = 2 1/5.

Thus, the equation y = 1/5x+ 2.2

Hope it helps <3

Answer 2

y=1/5x+11/5

Explanation:

Find the slope of the original line and use the point-slope formula y-y^1=m(x-x^1) to find line parallel to -x+5y=1

Hope this helps