Question

A student applies a constant horizontal 20 N force to a 12 kg box that is initially at rest. The student moves the box a distance of 3.0 m. What is the speed of the box at the end of the motion

Answer 1

u = 10.02m/s

Step-by-step explanation:

a = f/m

a = 20/12 = 1.67m/s²

U =2aS

u = 2 x 1.67 x 3

U = 10.02m/s