Question

PLEASSE HELP

If a line crosses the y-axis at (0, 1) and has a slope of 4/5, what is the equation of the line?
A 4y - 5x=5
B.y - 4x = 5
C. 5y + 4x = 5
D. 5y - 4x = 5

Answer 1

D.
`\boxed{5y-4x=5}`

Explanation:

Slope = m = 4/5

y - intercept = b = 1 (As from the point (0,1) , y-intercept is when x = 0)

So, the equation becomes

=>
`y = mx+b`

=>
`y = (4)/(5) x +1`

=>
`y - (4)/(5) x = 1`

Multiplying both sides by 5

=>
`5y-4x = 5`

Answer 2

The answer is option D.

Explanation:

Equation of the line using point (0, 1) and slope 4/5 is

`y - 1 = (4)/(5) (x - 0) \\ \\ 5y - 5 = 4x \\ \\ 5y - 4x = 5`

Hope this helps you