Question

Ill attach a pic because I dont know how to write this out

Answer 1

Distances:

a = π / 2 , b = π , c = 3π /2

Heights:

d = 1 , e = 0 , f = - 1

Formula used = for distance , we use:

`(theta)/(360) * 2\pi \: r`

length of arc = 1 m

`( (\pi)/(2) )/(2\pi) * 2\pi * 1`

`a \: = \: (\pi)/(2)`

B =
`(\pi)/(2\pi) * 2\pi * 1`

`= \pi`

C =
`( (3\pi)/(2) * 2\pi )/(2\pi)`

`= (3\pi)/(2)`

Heights:

If theta = π / 2 , d = 1

If theta = π , e = 0

If theta = 3π/2 , f = - 1

Please see the attached picture..

hope this helps..

Good luck on your assignment..