191k views
5 votes
01:37:49

The function f(x) = −(x + 5)(x + 1) is shown.

On a coordinate plane, a parabola opens down. It goes through (negative 5, 0), has a vertex at (negative 3, 4), and goes through (negative 1, 0).
What is the range of the function?

all real numbers less than or equal to 4
all real numbers less than or equal to −3
all real numbers greater than or equal to 4
all real numbers greater than or equal to −3

User MarengoHue
by
7.7k points

2 Answers

1 vote

Answer:

all real numbers less than or equal to 4

Explanation:

The leading coefficient is negative, so the vertex is a maximum. The y-value of the vertex (4) is the upper limit of the range.

The range is all real numbers less than or equal to 4. (first choice)

01:37:49 The function f(x) = −(x + 5)(x + 1) is shown. On a coordinate plane, a parabola-example-1
User Hilton Campbell
by
8.4k points
6 votes

Answer:

all real numbers less than or equal to 4

which agrees with the first answer option listed

Explanation:

The parabola opening down means that its two branches go on towards negative values with no limit. The maximum y-value that this parabola can reach is therefore the y-value of its vertex which is 4, given that the vertex coordinates are (3, 4).

Therefore, the Range of y-values can have any real number that is smaller than or equal to 4

User KSTN
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories