Answer: a = 8, x = 56, y = 68
Explanation:
Was there a description that stated this was a parallelogram?
Since that information was not provided....
I used the Law of Cosines to find x = 56°.
Congruent sides implies congruent angles so Center-Q-R = 56°.
Triangle Sum Theorem results in y = 68°
Vertical angles results in S-Center-P = 68°
Triangle sum Theorem results in S-P-Center = 68°
Now we can see that alternate interior angles are congruent, therefore PQRS is a parallelogram. Diagonals are bisected at the intersection so a = 8