Answer:
x1 = -5
x2 = 3
Explanation:
You have the following equation:
(1)
To find the solutions of the equation (1) you first eliminate the denominators of the equation, by multiplying the m.c.m, which is 5x, as follow:
![30-4x=2x^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/70yutsr6o11gl3xcv2rgw4rqupk1jm73tg.png)
Next, you write the previous equation in the general form ax^2 +bx+c=0, as follow:
![2x^2+4x-30=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/bqn9oyayoqc0lbuu354zjaiewtg7qhmyni.png)
Next, you use the quadratic formula to find the solutions:
![x_(1,2)=(-b\pm √(b^2-4(a)(c)))/(2a)\\\\a=2;\ \ b=4;\ \ c=-30\\\\x_(1,2)=(-4\pm √(4^2-4(2)(-30)))/(2(2))\\\\x_(1,2)=(-4\pm16)/(4)\\\\x_1=-5\\\\x_2=3](https://img.qammunity.org/2021/formulas/mathematics/high-school/n1l087b0d2at66nziy03k8jl64277mme7q.png)
Then, the solutions for the given equation are x1=-5 and x2=3