Question

An air-filled parallel-plate capacitor has plates of area 2.30 cm2 2 separated by 1.50 mm. The capacitor is connected to a 12.0-V battery. Find the value of its capacitance.

Answer 1

`1.357* 10^(-12)`

Step-by-step explanation:

Relevant Data provided

Area which indicates A = 2.3 cm^2 = 2.3 x 10^-4 m^2

Distance which indicates d = 1.50 x 10^-3 m

Voltage which indicates V = 12 V

According to the requirement, the computation of value of its capacitance is shown below:-

`Capacitance, C = (\epsilon oA)/(D)`

`= (= 8.854* 10^(-12)* 2.3* 10^(-4))/((1.5 * 10^(-3)))`

=
`1.357* 10^(-12)`

Therefore for computing the capacitance we simply applied the above formula.