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Based on my previous question I have posted.. Answer this.. It's the continuation

Table 7.3 is different ​

Based on my previous question I have posted.. Answer this.. It's the continuation-example-1

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Answer:

We don't know what solvent X and solvent Y are, but from the chart, we can see that in solvent X, hydrochloric acid can conduct electricity (bulb lights up), and react with calcium carbonate.

So, we can say the electrical conductivity when HCl is dissolved in solvent X is high, and when HCl is dissolved in solvent Y, the electrical conductivity is low (because light bulb doesn't light up).

Additionally, in solvent X, HCl ionizes, this shows the property of acids: reacts with carbonates to give CO2 (because CO2 reacts with lime water to make it cloudy).

In solvent Y, HCl does not ionize, so there is no reaction between acid and calcium carbonate.

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