Question

Find the center of the circle (x-2)^2+(y-8)^2=33

Answer 1

The center is (2,8)

Explanation:

The equation of a circle is written as

(x-h)^2+ (y-k)^2 = r^2

where ( h,k) is the center and r is the radius

(x-2)^2+(y-8)^2=33

The center is (2,8) and the radius is sqrt(33)