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A circular loop of wire of radius 10 cm carries a current of 6.0 A. What is the magnitude of the magnetic field at the center of the loop

User Ingweland
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1 Answer

7 votes

Answer:

3.77x10^-5T

Step-by-step explanation:

Magnetic field at center of the loop is given as

B=uo*I/2r =(4pi*10-7)*6/2*0.1

B=3.77*10-5Tor 37.7 uTi

User Robert Picard
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