Question

A village P is 10km from a lorry station,Q on a bearing 065°.another village R is 8km from Q on a bearing 155°.calculate;1.the distance of R from P to the nearest kilometer and 2.the bearing of R from P to the nearest degree.

Answer 1

Explanation:

find the difference between the two angles first:

155-65=90 degrees

d is the distance d:

d^2=a^2+b^2-2ab cos(90)

d^2=10^2+8^2-2(10)(8)cos(90)

d^2=164

d=√164=12.81

the bearing of R from P to the nearest degree:

180-155=35 degrees