Question

given the equation below which of the following shows the quadratic formula correctly applied? 3x^2-4x-12=0

Answer 1

`{3x}^(2) - 4x - 12 = 0`

`a = 3`

`b = - 4`

`c = - 12`

Formula:

`\boxed{x = \frac{ - b \pm \: \sqrt{ {b}^(2) - 4ac} }{2a} }`

Replacing:

`x = \frac{ -( - 4) \pm \sqrt{ { (- 4)}^(2) - 4(3)( - 12)} }{2(3)}`

Option: C).