Question

It takes 144 J of work to move 1.9 C of charge from the negative plate to the positive plate of a parallel plate capacitor. What voltage difference exists between the plates

Answer 1

The voltage difference between the plates of the parallel plate capacitor is 144 J.

Step-by-step explanation:

To determine the voltage difference between the plates of a parallel plate capacitor, we can use the formula V = Q/C, where V is the voltage, Q is the charge, and C is the capacitance. In this case, the charge Q is given as 1.9 C, and the work done to move the charge from the negative plate to the positive plate is given as 144 J. We can calculate the capacitance C by rearranging the formula: C = Q/V. Substituting the given values, we get C = 1.9 C / 144 J. Finally, we can calculate the voltage V by rearranging the formula: V = Q/C. Substituting the values, we get V = 1.9 C / (1.9 C / 144 J). Therefore, the voltage difference between the plates is 144 J.

Answer 2

151.58 V

Step-by-step explanation:

From the question,

The work done in a circuit in moving a charge is given as,

W = 1/2QV..................... Equation 1

Where W = Work done in moving the charge, Q = The magnitude of charge, V = potential difference between the plates.

make V the subject of the equation

V = 2W/Q.................. Equation 2

Given: W = 144 J. Q = 1.9 C

Substitute into equation 2

V = 2(144)/1.9

V = 151.58 V