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Ask Your Teacher An electric utility company supplies a customer's house from the main power lines (120 V) with two copper wires, each of which is 34.0 m long and has a resistance of 0.109 Ω per 300 m. (a) Find the potential difference at the customer's house for a load current of 116 A.

User TimB
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Answer:

The potential difference at the customer's house is 117.1 V.

Step-by-step explanation:

a) The potential difference at the customer's house can be calculated as follows:


\Delta V_(h) = \Delta V_(p) - \Delta V_(l)

Where:


V_(h): is the potential difference at the customer's house


V_(p): is the potential difference from the main power lines = 120 V


V_(l): is the potential difference from the lines


\Delta V_(h) = \Delta V_(p) - IR

The resistance, R, is:


(0.109 \Omega)/(300 m)*2*34.0 m = 0.025 \Omega

Now, the potential difference at the customer's house is:


\Delta V_(h) = 120 V - 116A*0.025 \Omega = 117.1 V

Therefore, the potential difference at the customer's house is 117.1 V.

I hope it helps you!

User Nhaht
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