114k views
4 votes
Is the relationship shown by the data linear? If so , model the data with an equation.

Is the relationship shown by the data linear? If so , model the data with an equation-example-1

1 Answer

3 votes

The data is linear.

The equation in slope intercept form is y = (-5/4)x - 53/4

The equation in standard form is 5x+4y = -53

========================================================

Step-by-step explanation:

We know the data is linear because each time x increases by 4, the value of y decreases by 5. The slope is m = (change in y)/(change in x) = -5/4

Use m = -5/4 and one row of x,y values (say x = -9 and y = -2 from the first row) to find the value of b

y = mx+b

-2 = (-5/4)(-9) + b

-2 = 45/4 + b

45/4+b = -2

b = -2 - 45/4

b = -8/4 - 45/4

b = (-8 - 45)/4

b = -53/4

Therefore we go from y = mx+b to y = (-5/4)x - 53/4

We can convert to standard form like so

y = (-5/4)x - 53/4

4y = -5x - 53 ... multiply every term by 4

5x+4y = -53 ... add 5x to both sides

-----------------------

To check the answer, plug in x = -9 and you should get y = -2 as a result

y = (-5/4)x - 53/4

y = (-5/4)*(-9) - 53/4

y = 45/4 - 53/4

y = (45-53)/4

y = -8/4

y = -2

We have confirmed the first row of the table. The other rows will be handled the same way.

User StefanoGermani
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.