Question

What is the solution to this system of linear equations? x − 3y = −2 x + 3y = 16

Answer 1

Answer: ( x = -32, y = -16 )

Explanation:

This can be represented by the three sides of an equilateral triangle.

x - 3y = -2x + 3y , simplify

x + 2x - 3y - 3y = 0

3x - 6y =0

x - 2y = 0 ---------------------- 1

x - 3y. = 16 ---------------------2

Solve using any methods

By elimination

y. = -16.

Substitute for y in any of the equations

x - 2y = 0

x. - 2(-16) = 0

x + 32 = 0

Therefore

x. = -32

Solution is ( -32, -16 )

Answer 2

so x=5 1/3 and

y= -2 2/3

Explanation:

x-3y= -2x+3y=16. First we need to move all variables to one side of the equation and whole numbers to the other side of the equation. I see

x-3y+2x-3y=16. -3y-3y equals to -6y. 2x+x=3x. so 3x-6y=16. Lets take out the -6y so our equation would be 3x=16. x would equal 5 1/3. Now lets put back -6y into our equation. Let's now substitute x as 0. 3 times 0 equals 0 so our equation would now be -6y=16 which equals to -2 2/3.

so x=5 1/3 and

y= -2 2/3