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45 votes
45 votes
The function p(x) = x(x - 5)(x − 2)(x+3) has four zeros. What is the smallest zero?

=
X =
1
1
2

X
3

User Tarik Huber
by
2.7k points

2 Answers

22 votes
22 votes

Answer:

x = -3

Explanation:

x(x-5)(x-2)(x+3) = 0 means at least one of these terms = 0

so

x = 0 or

x-5 = 0 then x = 5 or

x-2 = 0 then x = 2 or

x+3 = 0 then x= -3

User Nickpatrick
by
2.7k points
16 votes
16 votes

Answer: The smallest zero is -3.

Step-by-step explanation: Zeros of a function are the values of input for which the function gives 0 output.

Here, the given function is,

p(x) = x(x-5)(x-2)(x+3)

For finding the zeroes of p(x),

p(x) = 0

⇒ x(x-5)(x-2)(x+3) = 0,

⇒ x = 0 or x - 5 = 0 or x-2=0 or x+3=0

⇒ x = 0 or x = 5 or x = 2 or x = -3

Thus, the zeros of the given function are 0, 5, 2, -3

In which -3 is smallest.

User Yurii
by
2.4k points