Which shows one way to determine the factors of 4x3 + x2 - 8x - 2 by grouping?

Question

asked Jul 6, 2021 53.2k views

2 Answers

Dan Garant · Answer 1 · 2021-07-07T15:29:06+0000

Answer:

(4x+1)(x²-2)

Explanation:

one way to determine the factors of 4x^3 + x^2 - 8x - 2 by grouping:

x²(4x+1)-2(4x+1)

(4x+1)(x²-2)

Zhu Shengqi · Answer 2 · 2021-07-12T13:17:19+0000

Answer:

(x^2-2)(4x+1)

Explanation:

4x^3 + x^2 - 8x - 2

Group:

(4x^3 + x^2)+( - 8x - 2)

Factor out as much as possible: (The GCF)

x^2(4x+1)-2(4x+1)

Regroup:

(x^2-2)(4x+1)