Question

An aqueous solution of cobalt(II) fluoride, , is made by dissolving 6.04 grams of cobalt(II) fluoride in sufficient water in a 200. mL volumetric flask, and then adding enough water to fill the flask to the mark. What is the weight/volume percentage of cobalt(II) fluoride in the solution

Answer 1

`w/v\%=3.02(g)/(mL) \%`

Step-by-step explanation:

Hello,

In this case, we first define the formula for the calculation of weight/volume percentage considering cobalt (II) fluoride as the solute, water the solvent and the both of them as the solution:

`w/v\%=(mass_(solute))/(V_(solution))*100\%`

In such a way, since the mass of the solute is given as 6.04 g and the final volume of the solution 200 mL, the weight/volume percentage turns out:

`w/v\%=(6.04g)/(200mL)*100\%\\\\w/v\%=3.02(g)/(mL) \%`

Regards.