Question

If the average rate of the reaction A --->2B C is 1M/s, what is the average rate of formation (in M/s) of B over that same period of time

Answer 1

`r_B=2M/s`

Step-by-step explanation:

Hello,

In this case, since the average rate of reaction is related with the consumption of A which has an stoichiometric coefficient of 1, the rate of formation of B will be:

`r_B=2*1M/s\\\\r_B=2M/s`

By cause of the stoichiometric coefficient of B which doubles the average rate.

Best regards.