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Volume occupied 3.52x10^32 moluchles of Mathane (CH4) 1) At STP​
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4 votes
Volume occupied 3.52x10^32 moluchles
of Mathane (CH4)
1) At STP​

User Hanno Fietz
by
4.1k points

1 Answer

3 votes

Answer:

volume = 13097674418.528dm³

Step-by-step explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

User Marian Zburlea
by
4.3k points
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