Question

(04.02 LC)

What is the solution to the following system of equations?
X - 3y = 6
2x + 2y = 4

(-1, 3)
(3, -1)
(1, -3)
(-3, 1)​

Answer 1

B. ( 3 , - 1)

Explanation:

x - 3y = 6 Equation 1

2x + 2y = 4 Equation 2

x = 6 + 3y

2( 6 + 3y ) + 2y = 4

12 + 6y + 2y = 4

8y = - 8

y = - 1

x = 6 + 3(-1)

x = 6 - 3

x = 3

x = 3 y = - 1

( 3 , - 1)

Answer 2

The solution is

( 3 , - 1)

Explanation:

x - 3y = 6 ............ Equation 1

2x + 2y = 4 ............ Equation 2

Make x the subject in equation 1 and substitute it into equation 2

That's

x = 6 + 3y

2( 6 + 3y ) + 2y = 4

Expand and simplify

12 + 6y + 2y = 4

8y = - 8

Divide both sides by 8

y = - 1

Substitute y = - 1 into x = 6 + 3y

That's

x = 6 + 3(-1)

x = 6 - 3

x = 3

x = 3 y = - 1

( 3 , - 1)

Hope this helps you