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What is the equation of the following line written in slope-intercept form?

(-5, -1)
Oy=3/2x-13/3
Oy=-2/3x-13/3
Oy=2/3x-13/3​

What is the equation of the following line written in slope-intercept form? (-5, -1) Oy-example-1
User Davidxxx
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1 Answer

1 vote

Answer:

Option (2)

Explanation:

Let the equation of the line is,

y - y' = m(x - x')

where (x', y') is a point lying on the given line.

And m = slope of the line =
(y_2-y_1)/(x_2-x_1)

Line given in the graph passes through two points (-5, -1) and (-2, -3).

Slope of the line 'm' =
(-3+1)/(-2+5)

=
-(2)/(3)

Therefore, equation of the line passing through(-5, -1) and slope of the line =
-(2)/(3) will be,

y - (-1) =
-(2)/(3)[x-(-5)]


y+1=-(2)/(3)(x+5)


y=-(2)/(3)x-(10)/(3)-1


y=-(2)/(3)x-(13)/(3)

Option (2) will be the answer.

User Askia
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